Conversion of SO₂ Concentration from mg/m³ to PPM at 25°C
Question
Convert 160 mg/m³ of SO₂ concentration into PPM at 25°C.
Given Data
| Parameter | Value |
|---|---|
| SO₂ Concentration | 160 mg/m³ |
| Temperature | 25°C |
| Molecular Weight of SO₂ | 64 g/mol |
| Molar Volume at STP | 22.4 L/mol |
Step 1: Volume of Gas at 25°C
At STP (0°C and 1 atm), one mole of gas occupies:
V₁ = 22.4 litres/mol
Using Charles' Law:
V₁/T₁ = V₂/T₂
Where:
T₁ = 273 K
T₂ = 273 + 25 = 298 K
T₂ = 273 + 25 = 298 K
Therefore:
V₂ = 22.4 × (298 / 273)
V₂ = 24.45 litres/mol
Step 2: General Conversion Formula
For converting concentration from mg/m³ to PPM:
PPM = (mg/m³ × Molar Volume at Temperature) / Molecular Weight
Step 3: Substitute Values
PPM = (160 × 24.45) / 64
PPM = 3912 / 64
PPM = 61.13
160 mg/m³ of SO₂ = 61.13 PPM
Shortcut Formula for Examinations
At 25°C and 1 atmosphere pressure:
PPM = (mg/m³ × 24.45) / Molecular Weight
For SO₂:
PPM = (mg/m³ × 24.45) / 64
Exam Tip: Remember the value 24.45 for gases at 25°C. It is frequently used in Environmental Engineering and Air Pollution numerical problems.
Final Answer
SO₂ Concentration = 61.13 PPM

0 Comments