Numerical Example: Effective Height of Stack
Problem Statement
Determine the effective height of a stack using the following data:
| Parameter | Value |
|---|---|
| Physical Stack Height (h) | 150 m |
| Inside Diameter of Stack (D) | 1.0 m |
| Wind Velocity (u) | 3.5 m/s |
| Air Temperature (Ta) | 25°C |
| Atmospheric Pressure (P) | 1010 millibars |
| Stack Gas Velocity (Vs) | 12.5 m/s |
| Stack Gas Temperature (Ts) | 180°C |
Step 1: Convert Temperatures to Kelvin
Ta = 25 + 273 = 298 K
Ts = 180 + 273 = 453 K
Step 2: Holland's Equation for Plume Rise
Δh = (VsD/u) × [1.5 + 2.68 × 10-3 × P × D × ((Ts − Ta)/Ts)]
Step 3: Substitute the Given Values
Δh = (12.5 × 1.0 / 3.5)
× [1.5 + 2.68 × 10-3 × 1010 × 1.0 × ((453 − 298)/453)]
Step 4: Calculate Temperature Ratio
(453 − 298) / 453
= 155 / 453
= 0.3422
Step 5: Evaluate the Bracket Term
1.5 + (2.68 × 10-3 × 1010 × 0.3422)
1.5 + 0.926
= 2.426
Step 6: Calculate First Part
(12.5 × 1.0) / 3.5
= 3.571
Step 7: Calculate Plume Rise
Δh = 3.571 × 2.426
Δh = 8.67 m
Step 8: Calculate Effective Stack Height
Effective Stack Height is:
H = h + Δh
H = 150 + 8.67
H = 158.67 m
Smoke Plume
/
/
/
/
Δh = 8.67 m
↑
┌───────┐
│ │
│Stack │
│ │
│ │
│ │
└───────┘
↑
h = 150 m
──────────────────────── Ground Level
Effective Height (H) = 158.67 m
Plume Rise (Δh) = 8.67 m
Effective Stack Height (H) = 158.67 m
Important: The effective stack height is always greater than the physical stack height because the emitted gases continue to rise above the chimney due to momentum and buoyancy effects.
Quick Formula Summary
| Parameter | Formula |
|---|---|
| Plume Rise | Δh = (VsD/u)[1.5 + 2.68 × 10-3PD((Ts − Ta)/Ts)] |
| Effective Height | H = h + Δh |

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